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2x^2+15=8x-5
We move all terms to the left:
2x^2+15-(8x-5)=0
We get rid of parentheses
2x^2-8x+5+15=0
We add all the numbers together, and all the variables
2x^2-8x+20=0
a = 2; b = -8; c = +20;
Δ = b2-4ac
Δ = -82-4·2·20
Δ = -96
Delta is less than zero, so there is no solution for the equation
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